Problem
Given a natural number number, write a function solution that returns the total sum of all divisors of each number from 1 to number.
Constraints
numberis a natural number between 1 and 100 inclusive.
Test Case
| Test Case Number | number | return |
|---|---|---|
| 1 | 5 | 21 |
| 2 | 10 | 87 |
| 3 | 12 | 127 |
Explanation for Test Case 1
- When
number = 5, the divisors of each number from 1 to 5 are[1], [1, 2], [1, 3], [1, 2, 4], [1, 5]. The total sum is21.
Explanation for Test Case 2
- When
number = 10, the total sum of divisors of each number from 1 to 10 is87.
Explanation for Test Case 3
- When
number = 12, the total sum of divisors of each number from 1 to 12 is127.